A mover pushes a box of mass m = 56.0 kg along a horizontal floor a distance d = 2.50 m.The constant force exerted on the box by the mover makes an angle of 27.0° directed below the horizontal.Assume the floor is frictionless.If the work done by the mover is W = 200 J,what is the force exerted by the mover?
A)89.8 N
B)549 N
C)616 N
D)176 N

Question

Quizplus · Accepted Answer

The work done by a force is given by $W = Fd\cos(\theta)$, where $F$ is the magnitude of the force, $d$ is the distance over which the force is applied, and $\theta$ is the angle between the force and the direction of motion. Given that the work $W = 200\,J$, the distance $d = 2.50\,m$, and the angle $\theta = 27.0^\circ$, we can solve for $F$:$$200 = F \times 2.50 \times \cos(27.0^\circ)$$Solving for $F$ gives:$$F = \frac{200}{2.50 \times \cos(27.0^\circ)} \approx 89.8\,N$$

A Mover Pushes a Box of Mass M = 56