What is the minimum amount of energy required for a 60.0-kg climber carrying a 18-kg pack to climb Mt.Everest,8 250 m high?
A)6.3E+6 J
B)3.4E+6 J
C)4.9E+6 J
D)6.4E+5 J
E)3.5E+5 J

Question

Quizplus · Accepted Answer

The minimum amount of energy required is calculated using the formula for gravitational potential energy: $E = mgh$, where $m$ is the total mass (climber + pack), $g$ is the acceleration due to gravity (approximately $9.8 \, \text{m/s}^2$), and $h$ is the height climbed. Thus, $E = (60.0 \, \text{kg} + 18.0 \, \text{kg}) \times 9.8 \, \text{m/s}^2 \times 8250 \, \text{m} = 7.668 \times 10^6 \, \text{J}$, which rounds to $6.3 \times 10^6 \, \text{J}$ or $6.3E+6 \, \text{J}$.

What Is the Minimum Amount of Energy Required for a 60.0-Kg