A 10.0-kg box starts at rest and slides 3.90 m down a ramp inclined at an angle of 10° with the horizontal.If there is no friction between the ramp surface and crate,what is the velocity of the crate at the bottom of the ramp? (g = 9.8 m/s²) A)13.3 m/s B)3.64 m/s C)8.74 m/s D)8.68 m/s E)76.4 m/s

Question

Quizplus · Accepted Answer

The potential energy at the top of the ramp is equal to the kinetic energy at the bottom, since there is no friction. So,
mgh = 1/2mv^2
where m = 10.0 kg, h = 3.90 m sin(10°), and g = 9.8 m/s^2.
Solving for v gives v = √(2gh) = 3.64 m/s. So the correct answer is B.

A 100-Kg Box Starts at Rest and Slides 3