Adisa pulls a 35.0-N crate up a 4.00-m-long inclined plane at a constant velocity.If the plane is inclined at an angle of 39.0° to the horizontal and there is a constant force of friction of 13.0 N between the crate and the surface,what is the net change in potential energy of the crate?
A)88 J
B)−88 J
C)109 J
D)−109 J
E)None of these

Question

Quizplus · Accepted Answer

The net change in potential energy is calculated using the formula: ΔPE = mgh, where m is the mass, g is the acceleration due to gravity, and h is the height change. The height change (h) can be found using the sine of the incline angle: h = 4.00 m * sin(39.0°). The force of gravity acting on the crate is 35.0 N, which is equivalent to the weight (mg). Therefore, ΔPE = 35.0 N * 4.00 m * sin(39.0°) = 88 J.

Adisa Pulls a 35