Water flows over a section of Niagara Falls at a rate of 1.30 × 10⁶ kg/s and falls 52.0 m.What is the power dissipated by the waterfall? A)6.6E+8 W B)6.8E+7 W C)4.0E+7 W D)5.3E+8 W E)8.6E+6 W

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Quizplus · Accepted Answer

The power dissipated by the waterfall can be calculated using the formula for gravitational potential energy, which is P = mgh, where m is the mass flow rate (1.30 × 10^6 kg/s), g is the acceleration due to gravity (9.8 m/s^2), and h is the height (52.0 m). Substituting these values, we get P = (1.30 × 10^6 kg/s)(9.8 m/s^2)(52.0 m) = 6.6 × 10^8 W.

Water Flows Over a Section of Niagara Falls at a Rate