A satellite engine has an exhaust speed of 2.80 × 10⁴ m/s and ejects ionized gas at a rate of 2.50 × 10^-6 kg/s.What is the instantaneous thrust of the engine? A)8.93 × 10^-11 N B)7.00 × 10^-2 N C)5.30 × 10² N D)1.12 × 10¹⁰ N

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Quizplus · Accepted Answer

Thrust can be calculated using the formula $F = \dot{m} \times v$, where $\dot{m}$ is the mass flow rate and $v$ is the exhaust velocity. Substituting the given values, $F = 2.50 \times 10^{-6} \, \text{kg/s} \times 2.80 \times 10^{4} \, \text{m/s} = 7.00 \times 10^{-2} \, \text{N}$.

​A Satellite Engine Has an Exhaust Speed of 2

A Satellite Engine Has an Exhaust Speed of 2