A Ferris wheel,rotating initially at an angular speed of 0.50 rad/s,accelerates over a 7.0-s interval at a rate of 0.040 rad/s².What is its angular speed after this 7.0-s interval? A)0.20 rad/s B)0.30 rad/s C)0.46 rad/s D)0.78 rad/s

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Quizplus · Accepted Answer

The final angular speed can be calculated using the formula: final angular speed = initial angular speed + (angular acceleration * time). Substituting the given values: 0.50 rad/s + (0.040 rad/s^2 * 7.0 s) = 0.50 rad/s + 0.28 rad/s = 0.78 rad/s.

A Ferris Wheel,rotating Initially at an Angular Speed of 0