At an altitude of 5 times the radius of the Earth,the acceleration due to gravity is
A)g/5.
B)5g.
C)g/25.
D)not given.

Question

Quizplus · Accepted Answer

At an altitude of 5 times the radius of the Earth, the distance between the center of the Earth and the object becomes 6 times the radius of the Earth.

Using the formula for acceleration due to gravity, g' = (GM)/(r')^2, where G is the gravitational constant, M is the mass of the Earth, and r' is the distance between the center of the Earth and the object, we can find the acceleration due to gravity at this altitude:

g' = (GM)/(6R)^2 = g/36

where g is the acceleration due to gravity at the Earth's surface (approximately 9.81 m/s^2).

Therefore, g' = g/36, which is equivalent to (1/6)^2 times g, or g/36.

Thus, the correct answer is C) g/25.

At an Altitude of 5 Times the Radius of the Earth,the