A 5.0-kg mass is placed at (3.0,4.0)m,and a 6.0-kg mass is placed at (3.0,−4.0)m.What is the moment of inertia of this system of masses about the x axis? A)280 kg·m² B)33 kg·m² C)176 kg·m² D)99 kg·m² E)44 kg·m²

Question

Quizplus · Accepted Answer

The moment of inertia (I) of a system of particles can be calculated using the formula:

I = Σm_i * r_i^2

where m_i is the mass of each particle and r_i is the perpendicular distance of each particle from the axis of rotation (in this case, the x axis).

For the given system of masses, the moment of inertia about the x axis can be calculated as:

I = (5 kg * 4 m^2) + (6 kg * 4 m^2)
  = 20 kg·m^2 + 24 kg·m^2
  = 44 kg·m^2

Therefore, the best choice is C - 176 kg·m^2.

A 50-Kg Mass Is Placed at (3