How deep under the surface of a lake would the pressure be double that at the surface? (1 atm = 1.01 × 10⁵ Pa) A)1.00 m B)9.80 m C)10.3 m D)32.2 m

Question

Quizplus · Accepted Answer

The pressure at a certain depth in a liquid depends on the density and height of the liquid column above that depth. Using the equation P = ρgh, where P is the pressure, ρ is the density of the liquid, g is the acceleration due to gravity, and h is the depth, we can set the pressure at double the surface pressure and solve for h.

2P(surface) = ρgh
2(1.01 × 10^5 Pa) = 1000 kg/m^3 × 9.81 m/s^2 × h
h = 10.3 m

Therefore, the depth at which the pressure is double the surface pressure is 10.3 m. Choice C is the best answer.

How Deep Under the Surface of a Lake Would the Pressure