A fountain sends water to a height of 113 m.What must be the pressurization (above atmospheric)of the underground water system? (1 atm = 10⁵ N/m²) A)1.0 atm B)47.1 atm C)12.1 atm D)11.1 atm E)0.115 atm

Question

Quizplus · Accepted Answer

To find the required pressurization, we can use the formula for pressure due to a column of fluid, $P = \frac{h\rho g}{\rho_{\text{atm}}}$, where $h = 113\,m$ is the height of the water column, $\rho = 1000\,kg/m^3$ is the density of water, $g = 9.8\,m/s^2$ is the acceleration due to gravity, and $\rho_{\text{atm}} = 101,000\,N/m^2$ is the atmospheric pressure. Plugging in the values, we get $P = \frac{113 \times 1000 \times 9.8}{101,000} \approx 11.1\,atm$. This pressure is above atmospheric pressure, so the correct answer is 11.1 atm.

A Fountain Sends Water to a Height of 113 M