An ideal fluid,of density 900 kg/m³,flows at 4.80 m/s through a level pipe with radius of 0.22 cm.The pressure in the fluid is 1.3 × 10⁵ N/m².This pipe connects to a second level pipe,with radius of 0.72 cm.Find the speed of flow in the second pipe. A)51 m/s B)1.5 m/s C)0.45 m/s D)16 m/s E)4.9 m/s

Question

Quizplus · Accepted Answer

We can use the principle of continuity, which states that the mass flow rate (ρAv) of an ideal fluid is constant along a horizontal pipe. So, we can write:

ρ1A1v1 = ρ2A2v2

where ρ1 and ρ2 are the densities of the fluid in the first and second pipes, respectively; A1 and A2 are the cross-sectional areas of the pipes; v1 and v2 are the speeds of flow in the first and second pipes, respectively.

Since the fluid is ideal, its density is constant. Therefore, we can simplify the above equation to:

A1v1 = A2v2

Solving for v2, we get:

v2 = (A1/A2) v1

Substituting the given values, we get:

v2 = (π(0.22 cm)² / π(0.72 cm)²)(4.80 m/s) = 0.45 m/s

Therefore, the answer is (C) 0.45 m/s.

An Ideal Fluid,of Density 900 Kg/m3,flows at 4

An Ideal Fluid,of Density 900 Kg/m³,flows at 4