A fluid has a density of 1 040 kg/m³.If it rises to a height of 1.60 cm in a 1.50-mm diameter capillary tube,what is the surface tension of the liquid? Assume a contact angle of zero. A)0.0612 N/m B)0.122 N/m C)6.12 N/m D)0.245 N/m E)12.2 N/m

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The surface tension ($\gamma$) of the liquid can be calculated using the formula for capillary rise: $\gamma = \frac{\rho g h r}{2\cos(\theta)}$, where $\rho$ is the density of the fluid, $g$ is the acceleration due to gravity, $h$ is the height the fluid rises in the capillary, $r$ is the radius of the capillary tube, and $\theta$ is the contact angle. Given $\rho = 1040 \, \text{kg/m}^3$, $g = 9.8 \, \text{m/s}^2$, $h = 0.016 \, \text{m}$ (converted from 1.60 cm), $r = 0.00075 \, \text{m}$ (half of the diameter, which is 1.50 mm or 0.0015 m), and $\theta = 0$ (which makes $\cos(\theta) = 1$), substituting these values into the formula gives $\gamma = 0.0612 \, \text{N/m}$.

A Fluid Has a Density of 1 040 Kg/m3

A Fluid Has a Density of 1 040 Kg/m³