The length of a 25-m wire increases by 0.25 cm when it is heated from 20°C to 90°C.What is the coefficient of linear expansion of the wire? A)1.43 × 10^-6/ºC B)1.43 × 10^-4/ºC C)8.93 × 10^-4/ºC D)8.93 × 10^-2/ºC

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Quizplus · Accepted Answer

The coefficient of linear expansion ($\alpha$) can be calculated using the formula $\alpha = \frac{\Delta L}{L_0 \Delta T}$, where $\Delta L$ is the change in length, $L_0$ is the original length, and $\Delta T$ is the change in temperature. Given $\Delta L = 0.25$ cm (or 0.0025 m), $L_0 = 25$ m, and $\Delta T = 90°C - 20°C = 70°C$, substituting these values gives $\alpha = \frac{0.0025}{25 \times 70} = 1.43 \times 10^{-6} /°C$.

The Length of a 25-M Wire Increases by 0