Two moles of nitrogen gas are contained in an enclosed cylinder with a movable piston.If the gas temperature is 250 K,and the pressure is 1.10 × 10⁶ N/m²,what is the volume? (R = 8.31 J/mol⋅K) A)1.89 × 10−³ m³ B)3.78 × 10−³ m³ C)4.72 × 10−³ m³ D)7.55 × 10−³ m³ E)2.83 × 10−³ m³

Question

Quizplus · Accepted Answer

Using the ideal gas law PV = nRT, where n = 2 moles, R = 8.31 J/mol⋅K, T = 250 K, and P = 1.10 × 10^6 N/m^2, the volume V is calculated as V = (nRT)/P = (2 * 8.31 * 250) / (1.10 × 10^6) = 3.78 × 10^−3 m^3.

Two Moles of Nitrogen Gas Are Contained in an Enclosed