A waterfall is 128 m high.What is the increase in water temperature at the bottom of the falls if all the initial potential energy goes into heating the water? (g = 9.8 m/s²,c_w = 4 186 J/kg⋅°C) A)0.15°C B)0.30°C C)0.90°C D)0.37°C E)0.60°C

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Quizplus · Accepted Answer

The potential energy converted to heat is mgh = mcΔT. Solving for ΔT gives ΔT = gh/c. Substituting the given values, ΔT = (9.8 m/s² * 128 m) / 4186 J/kg°C = 0.30°C.

A Waterfall Is 128 M High