A piece of copper of mass 110 g is being drilled through with a ¹/₂" electric drill.The drill operates at 25.0 W and takes 25.0 s to bore through the copper.If all the energy from the drill heats the copper,find the copper's increase in temperature.c_copper = 387 J/kg⋅°C.

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Quizplus · Accepted Answer

The energy transferred to the copper is equal to the power of the drill times the time it operates, which is $25.0\, \text{W} \times 25.0\, \text{s} = 625\, \text{J}$. The mass of the copper is $0.110\, \text{kg}$, and the specific heat capacity of copper is $387\, \text{J/kg}\cdot\text{°C}$. The increase in temperature ($\Delta T$) can be found using the formula $\Delta T = \frac{Q}{m \cdot c}$, where $Q$ is the heat energy transferred, $m$ is the mass, and $c$ is the specific heat capacity. Substituting the given values, $\Delta T = \frac{625}{0.110 \cdot 387} \approx 14.7\, \text{°C}$.

A Piece of Copper of Mass 110 G Is Being