A person has a thermal conductivity of 0.18 W/m·K between his inner core and his skin with an effective shell thickness of 1.30 cm between his core and skin.If his inner core is at the normal 98.6°F,and his skin has a surface area of 1.62 m²,what will be his rate of loss of thermal energy due to conduction through his skin if his skin temperature is 28.3°C?

Question

Quizplus · Accepted Answer

First, we need to convert the core temperature from Fahrenheit to Celsius:

98.6°F = 37°C

Next, we can use the following formula to calculate the rate of thermal energy loss:

Q = k*A*(T1-T2)/d

where Q is the thermal energy loss, k is the thermal conductivity, A is the surface area, T1 is the core temperature, T2 is the skin temperature, and d is the effective shell thickness.

Plugging in the numbers, we get:

Q = 0.18 W/m·K * 1.62 m² * (37°C - 28.3°C)/(0.013 m)

Q = 195 W

Therefore, the rate of loss of thermal energy due to conduction through his skin is 195 W. The correct answer choice is D).

A Person Has a Thermal Conductivity of 0