A mass on a spring vibrates in simple harmonic motion at a frequency of 4.20 Hz and an amplitude of 7.50 cm.If the mass of the object is 0.260 kg,what is the spring constant?
A)6.86 N/m
B)696 N/m
C)181 N/m
D)24.1 N/m
E)339 N/m

Question

Quizplus · Accepted Answer

The frequency of simple harmonic motion is given by:

f = 1/(2π) √(k/m)

where k is the spring constant and m is the mass.

Substituting the given values, we get:

4.20 = 1/(2π) √(k/0.260)

Solving for k, we get:

k = (4π²)(0.260)(4.20)² = 181 N/m

Therefore, the spring constant is 181 N/m, which is given by choice (C).

A Mass on a Spring Vibrates in Simple Harmonic Motion