If two adjacent frequencies of an organ pipe closed at one end are 385 Hz and 578 Hz,what is the length of the organ pipe? (v_sound = 340 m/s) A)0.44 m B)0.59 m C)1.4 m D)0.88 m E)1.8 m

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Quizplus · Accepted Answer

For a closed organ pipe, the frequencies are given by f_n = n(v/4L), where n is an odd integer. The difference between two adjacent frequencies is (n+2 - n)(v/4L) = 2(v/4L). Given the difference is 578 Hz - 385 Hz = 193 Hz, we have 193 = 2(v/4L). Solving for L gives L = v/(4*193) = 340/(4*193) = 0.88 m.

If Two Adjacent Frequencies of an Organ Pipe Closed at One