A parallel-plate capacitor has a capacitance of 25 µF.What potential difference across the plates is required to store 7.2 × 10−⁴ C on this capacitor? A)2.9E+1 V B)3.6E+1 V C)4.5E+9 V D)2.9E-1 V E)4.5E+5 V

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Quizplus · Accepted Answer

The potential difference (V) required can be found using the formula $V = \frac{Q}{C}$, where $Q = 7.2 \times 10^{-4} C$ and $C = 25 \mu F = 25 \times 10^{-6} F$. Plugging in the values, $V = \frac{7.2 \times 10^{-4}}{25 \times 10^{-6}} = 28.8 V$, which is approximately $2.9 \times 10^1 V$.

A Parallel-Plate Capacitor Has a Capacitance of 25 µF