A 3.5-μF capacitor is attached to a 20-V power supply.How much energy is stored in the capacitor?

Question

Quizplus · Accepted Answer

The energy stored in a capacitor can be calculated using the formula $E = \frac{1}{2}CV^2$, where $E$ is the energy in joules, $C$ is the capacitance in farads, and $V$ is the voltage in volts. Plugging in the given values: $E = \frac{1}{2} \times 3.5 \times 10^{-6} \, \text{F} \times (20 \, \text{V})^2 = 7.0 \times 10^{-4} \, \text{J}$.

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