A lightbulb drawing a current of 0.60 A is run for 2.0 hours.How many electrons pass through the bulb during this process? A)2.7 × 10²² B)1.4 × 10¹⁹ C)5.4 × 10²⁵ D)4.3 × 10³

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Quizplus · Accepted Answer

The number of electrons can be calculated using the formula: number of electrons = (current in amperes × time in seconds) / elementary charge. First, convert 2.0 hours to seconds (2.0 hours * 3600 seconds/hour = 7200 seconds). The elementary charge is approximately 1.6 × 10^-19 coulombs. Therefore, the calculation is (0.60 A * 7200 s) / (1.6 × 10^-19 C) = 2.7 × 10^22 electrons.

A Lightbulb Drawing a Current of 0