If a metallic wire of cross-sectional area 4.0 × 10−⁶ m² carries a current of 7.0 A and has a mobile charge density of 4.24 × 10²⁸ carriers/m³,what is the average drift velocity of the mobile charge carriers? (charge value = 1.6 × 10−¹⁹ C) A)1.8E+3 m/s B)1.7E+3 m/s C)4.1E-4 m/s D)2.6E-4 m/s E)7.0E-6 m/s

Question

Quizplus · Accepted Answer

The formula for average drift velocity is v = I/(nAq), where I is current, n is the mobile charge density, A is cross-sectional area, and q is the charge value.

Substituting the given values, we get v = (7.0 A)/[(4.24 × 10^28 carriers/m^3) × (4.0 × 10^-16 m^2) × (1.6 × 10^-19 C)]

Simplifying, we get v = 2.6 × 10^-4 m/s.

Therefore, the answer is D) 2.6E-4 m/s.

If a Metallic Wire of Cross-Sectional Area 4