A metal wire has a resistance of 31 Ω under room temperature conditions of 15°C.When the wire is heated to 81°C the resistance increases by 0.65 Ω.What is the temperature coefficient of resistivity of this metal?

Question

Quizplus · Accepted Answer

The temperature coefficient of resistivity ($\alpha$) can be calculated using the formula $\alpha = \frac{\Delta R}{R_0 \Delta T}$, where $\Delta R = 0.65 \Omega$, $R_0 = 31 \Omega$, and $\Delta T = 81°C - 15°C = 66°C$. Plugging these values in gives $\alpha = \frac{0.65}{31 \times 66} = 3.2 \times 10^{-4} °C^{-1}$.

A Metal Wire Has a Resistance of 31 Ω Under