If a 500-W heater carries a current of 4.00 A,what is the resistance of the heating element?
A)85.7 Ω
B)42.8 Ω
C)31.3 Ω
D)11.2 Ω

Question

Quizplus · Accepted Answer

The resistance can be calculated using the formula $P = I^2R$, where $P$ is the power (500 W), $I$ is the current (4.00 A), and $R$ is the resistance. Rearranging the formula to solve for $R$ gives $R = P / I^2$. Substituting the given values, $R = 500 / (4.00)^2 = 500 / 16 = 31.25 \Omega$, which rounds to 31.3 Ω.

If a 500-W Heater Carries a Current of 4