A solar panel measures 80 cm × 57 cm.In direct sunlight,the panel delivers 3.1 A at 15 V.If the intensity of sunlight is 1 000 W/m²,what is the efficiency of the solar panel in converting solar energy into electrical energy?

Question

Quizplus · Accepted Answer

Firstly, we need to calculate the area of the solar panel by multiplying its length and breadth in meters:
Area = (80 cm × 57 cm) ÷ (100 cm/m)² = 0.456 m²

Next, we can calculate the power output of the solar panel in direct sunlight:
Power = Current × Voltage = 3.1 A × 15 V = 46.5 W

We can now determine the intensity of sunlight on the solar panel:
Sunlight intensity = Power ÷ Area = 46.5 W ÷ 0.456 m² = 102 W/m²

Finally, we can calculate the efficiency of the solar panel:
Efficiency = (Power output ÷ Solar energy input) × 100%
Efficiency = (46.5 W ÷ 1020 W) × 100% = 4.56%

Therefore, the best choice is C with an efficiency of 10%.

A Solar Panel Measures 80 Cm × 57 Cm