Three 4.00-Ω resistors are connected in parallel to a 10.4-V battery.What is the current in any one of the resistors?
A)14.4 A
B)6.76 A
C)2.60 A
D)41.6 A
E)6.40 A

Question

Quizplus · Accepted Answer

First, we need to calculate the total resistance of the circuit, which can be found using the formula:

1/R_total = 1/R1 + 1/R2 + 1/R3

Where R1, R2, and R3 are the resistances of the three resistors connected in parallel.

1/R_total = 1/4.00 Ω + 1/4.00 Ω + 1/4.00 Ω

1/R_total = 0.75 Ω

R_total = 1/0.75 Ω

R_total = 1.33 Ω

Next, we can use Ohm's Law to find the current in any one of the resistors:

I = V/R

I = 10.4 V / 4.00 Ω

I = 2.60 A

Therefore, the answer is C) 2.60 A.

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