In a circuit,a current of 1.10 A is drawn from a battery.The current then divides and passes through two resistors in parallel.One of the resistors has a value of 66 Ω and the current through it is 0.480 A.What is the value of the other resistor?
A)28.8 Ω
B)51.1 Ω
C)151 Ω
D)20.1 Ω

Question

Quizplus · Accepted Answer

Using Kirchhoff's Current Law (KCL), we know that the current through the second resistor is equal to the total current minus the current through the first resistor:
I2 = Itotal - I1
I2 = 1.10A - 0.480A
I2 = 0.62A
Using Ohm's Law for each resistor:
V = IR
For the first resistor:
V1 = 0.480A * 66Ω
V1 = 31.68V
For the second resistor:
V2 = 0.62A * R
The voltage across both resistors is the same, so:
V2 = 1.10A * Rtotal - V1
0.62A * R = 1.10A * Rtotal - V1
0.62A * R = 1.10A * (66Ω + R) - 31.68V
Solving for R gives:
R = 51.1Ω

In a Circuit,a Current of 1