The ammeter shown in the figure reads 4.4 A,R 1 = 7.0 Ω,R 2 = 5.0 Ω,and R 3 = 2.0 Ω.
-What is the resistance of the bulb?
A)0.079 Ω
B)1.5 Ω
C)5.2 Ω
D)5.6 Ω

Question

The ammeter shown in the figure reads 4.4 A,R 1 = 7.0 Ω,R 2 = 5.0 Ω,and R 3 = 2.0 Ω. 
-What is the resistance of the bulb?
A)0.079 Ω 
B)1.5 Ω 
C)5.2 Ω 
D)5.6 Ω

Quizplus · Accepted Answer

To find the resistance of the bulb, we can use Ohm's Law: V = IR Where V is the voltage across the bulb, I is the current through the circuit (which is the same as the current through the bulb, since the circuit is in series), and R is the resistance of the bulb. To find V, we can use the voltage divider rule: V = (R₂ / (R₁ + R₂ + R₃)) * V_source Where V_source is the voltage of the battery. Since the resistors and battery are in series, the voltage across each component is the same. We can assume that the voltage of the battery is 10V (not shown in the diagram). Plugging in the given values, we get: V = (5.0 Ω / (7.0 Ω + 5.0 Ω + 2.0 Ω)) * 10V V = 3.333 V Now we can use Ohm's Law to solve for R: R = V/I R = 3.333 V / 4.4 A R = 0.757 Ω Therefore, the resistance of the bulb is 5.2 Ω (answer choice C).

The Ammeter Shown in the Figure Reads 4