An electron which moves with a speed of 4.5 × 10⁴ m/s perpendicular to a uniform magnetic field of 0.57 T experiences a force of what magnitude? (e = 1.6 × 10−¹⁹ C) A)zero B)6.57E-33 N C)2.05E-15 N D)1.26E-14 N E)4.10E-15 N

Question

Quizplus · Accepted Answer

The equation for the magnetic force on a charged particle is F = qvBsin(θ), where q is the charge of the particle, v is the velocity of the particle, B is the magnetic field, and θ is the angle between v and B.

In this case, the electron is moving perpendicular to the magnetic field, so θ = 90° and sin(θ) = 1. Plugging in the given values, we get:

F = (1.6 × 10−19 C)(4.5 × 10^14 m/s)(0.57 T)(1) = 4.10 × 10−15 N

The closest answer choice is E.

An Electron Which Moves with a Speed of 4