A proton moves through a magnetic field of magnitude 1.40 T with speed 5.00 *10⁶m/s.What is the magnitude of the maximum acceleration of the proton? The mass of a proton is 1.67 *10^-27 kg,and its charge is 1.6 *10^-19 C. A)3.42E+14 m/s B)6.71E+14 m/s C)3.35E+21 m/s D)1.71E+21 m/s

Question

Quizplus · Accepted Answer

The maximum acceleration of a charged particle moving through a magnetic field is given by
a = (q/m)Bv
where q is the charge of the particle, m is its mass, B is the magnetic field strength, and v is its velocity.
Substituting the given values, we get
a = (1.6E-19 C / 1.67E-27 kg) * 1.40 T * 5.00E6 m/s
a = 6.71E14 m/s^2
Therefore, the magnitude of the maximum acceleration of the proton is 6.71E14 m/s^2. The correct answer is B.

A Proton Moves Through a Magnetic Field of Magnitude 1