A 198-m-long wire carrying a current of 3.5 A will be accompanied by a magnetic field of what strength at a distance of 0.054 m from the wire? (magnetic permeability in empty space µ₀ = 4π × 10−⁷ T⋅m/A)

Question

Quizplus · Accepted Answer

The magnetic field produced by a current-carrying wire at a distance r is given by the formula:

B = μ₀I/(2πr)

where B is the magnetic field, I is the current, r is the distance, and μ₀ is the magnetic permeability in empty space.

Substituting the given values, we get:

B = (4π × 10−7 T⋅m/A) × 3.5 A /(2π × 0.054 m)

= 1.3 × 10−5 T

Therefore, the magnetic field at a distance of 0.054 m from the wire is 1.3 × 10−5 T.
The correct choice is C.

A 198-M-Long Wire Carrying a Current of 3