Two parallel conductors each of 0.34 m length,separated by 6.4 × 10−³ m and carrying 4.8 A in opposite directions,will experience what type and magnitude of mutual force? (magnetic permeability in empty space µ₀ = 4π × 10−⁷ T⋅m/A) A)attractive,2.1E-3 N B)repulsive,2.1E-3 N C)attractive,2.4E-4 N D)repulsive,2.4E-4 N E)zero

Question

Quizplus · Accepted Answer

The mutual force between two parallel conductors carrying current is given by:

$F = \frac{\mu_0 I_1 I_2 l}{2 \pi d}$, where
$\mu_0 =$ magnetic permeability in empty space $= 4 \pi 	imes 10^{-7} 	ext{T}\cdot	ext{m/A}$ (given),
$I_1 = I_2 = 4.8$ A (given),
$l = 0.34$ m (given),
$d = 6.4 	imes 10^{-10}$ m (given).

Plugging in the values, we get:

$F = \frac{(4\pi 	imes 10^{-7} 	ext{T}\cdot	ext{m/A})(4.8	ext{ A})(4.8	ext{ A})(0.34	ext{ m})}{2\pi(6.4	imes 10^{-10}	ext{ m})}$

$F \approx 2.4 	imes 10^{-4}$ N

The two parallel conductors carrying current will experience a repulsive force due to the current flowing in opposite directions. Therefore, the correct answer is (D) repulsive, 2.4E-4 N.

Two Parallel Conductors Each of 0