A solenoid with 568 turns,0.19 m long,carrying a current of 3.5 A and with a radius of 10−² m will have what strength magnetic field at its center? (magnetic permeability in empty space µ₀ = 4π × 10−⁷ T⋅m/A)

Question

Quizplus · Accepted Answer

The magnetic field inside a solenoid is given by B = μ₀ * (N/L) * I, where N is the number of turns, L is the length, and I is the current. Substituting the given values: B = (4π × 10⁻⁷ T⋅m/A) * (568/0.19 m) * 3.5 A = 1.3E-2 T.

A Solenoid with 568 Turns,0