A uniform 1.72-T magnetic field passes through the plane of a wire loop 0.46 m² in area.What flux passes through the loop when the direction of the 1.72-T field is at a 38.4° angle to the normal of the loop plane? A)2.9 T⋅m² B)0.49 T⋅m² C)0.62 T⋅m² D)0.63 T⋅m² E)0.79 T⋅m²

Question

Quizplus · Accepted Answer

The magnetic flux is given by Φ = B * A * cos(θ), where B is the magnetic field strength, A is the area, and θ is the angle between the field and the normal to the loop. Substituting the given values: Φ = 1.72 T * 0.46 m² * cos(38.4°) ≈ 0.62 T⋅m².

A Uniform 1