A loop of area 0.384 m² is in a uniform 0.0565-T magnetic field.If the flux through the loop is 6.10 × 10-³ T·m²,what angle does the normal to the plane of the loop make with the direction of the magnetic field? A)73.7° B)89.3° C)16.3° D)76.0º E)This is not possible.

Question

Quizplus · Accepted Answer

The magnetic flux (Φ) is given by Φ = B * A * cos(θ), where B is the magnetic field, A is the area, and θ is the angle between the magnetic field and the normal to the loop. Solving for θ, we get cos(θ) = Φ / (B * A). Substituting the given values, cos(θ) = (6.10 × 10^-3) / (0.0565 * 0.384), which gives θ ≈ 73.7°.

A Loop of Area 0