A square coil,enclosing an area with sides 2.75 cm long,is wrapped with 1 875 turns of wire.A uniform magnetic field perpendicular to its plane is turned on and increases to 0.390 T during an interval of 1.70 s.What average voltage is induced in the coil?

Question

Quizplus · Accepted Answer

The average voltage induced in the coil is given by the equation:ε = -N * (ΔΦ / Δt)where:ε is the average voltage induced in the coil (in volts)N is the number of turns in the coilΔΦ is the change in magnetic flux through the coil (in webers)Δt is the time interval over which the change in magnetic flux occurs (in seconds)In this problem, we are given the following information:N = 1875 turnsΔΦ = B * A = (0.390 T) * (2.75 cm * 2.75 cm) = 2.71 * 10^-4 WbΔt = 1.70 sSubstituting these values into the equation, we get:ε = -N * (ΔΦ / Δt) = -(1875 turns) * (2.71 * 10^-4 Wb / 1.70 s) = 0.325 VTherefore, the average voltage induced in the coil is 0.325 V, which corresponds to choice A.

A Square Coil,enclosing an Area with Sides 2