An RL series circuit has the following components: 9.2-mH coil,1.2-Ω resistor,16-V battery,ammeter and switch.What is the time constant of this circuit?
A)1.3E+2 s
B)7.7E-3 s
C)1.4E-3 s
D)6.9E-4 s
E)1.2E-1 s

Question

An RL series circuit has the following components: 9.2-mH coil,1.2-Ω resistor,16-V battery,ammeter and switch.What is the time constant of this circuit?
A)1.3E+2 s
B)7.7E-3 s
C)1.4E-3 s
D)6.9E-4 s
E)​1.2E-1 s

Quizplus · Accepted Answer

The time constant ($\tau$) of an RL circuit is calculated using the formula $\tau = \frac{L}{R}$, where $L$ is the inductance in henries (H) and $R$ is the resistance in ohms ($\Omega$). Given $L = 9.2 \times 10^{-3}$ H (9.2 mH) and $R = 1.2 \Omega$, $\tau = \frac{9.2 \times 10^{-3}}{1.2} = 7.67 \times 10^{-3}$ s, which is approximately $7.7 \times 10^{-3}$ s.

An RL Series Circuit Has the Following Components: 9