An RL circuit has L = 0.45 H and R = 3.5 Ω.It is connected to a battery with ε = 25 V at time t = 0.Find the energy stored in the inductor when the current in the circuit is 0.25 A.
A)14 mJ
B)28 J
C)110 J
D)3.2 mJ
E)800 J

Question

Quizplus · Accepted Answer

The energy stored in an inductor is given by the formula $E = \frac{1}{2}LI^2$, where $E$ is the energy in joules, $L$ is the inductance in henries, and $I$ is the current in amperes. Substituting the given values, $E = \frac{1}{2} \times 0.45 \times (0.25)^2 = 0.0140625$ joules, or 14 mJ.

An RL Circuit Has L = 0