In the inductor of a 59-Hz AC series circuit,the peak voltage precedes the peak current in each cycle by what time interval?
A)1.7E-2 s
B)4.2E-3 s
C)8.5E-3 s
D)3.4E-2 s
E)6.8E-2 s

Question

Quizplus · Accepted Answer

The time interval between the peak voltage and the peak current in an inductor in an AC series circuit is given by:

δt = π/2f

where f is the frequency of the AC circuit. Substituting f = 59 Hz, we get:

δt = π/2(59) ≈ 4.2E-3 s

Therefore, the correct choice is B.

In the Inductor of a 59-Hz AC Series Circuit,the Peak