What is the average power dissipation in an RLC series circuit in which R = 177 Ω,L = 0.060 H,and C = 8.65 µF driven at resonance by a 163-V (rms)source?
A)150 W
B)138 W
C)147 W
D)144 W
E)1 370 W

Question

Quizplus · Accepted Answer

The average power dissipation in an RLC series circuit at resonance is given by:P = (Vrms^2) / Rwhere Vrms is the rms voltage of the source and R is the resistance of the circuit.In this case, Vrms = 163 V and R = 177 Ω, so:P = (163 V)^2 / 177 Ω = 147 WTherefore, the correct answer is C) 147 W.

What Is the Average Power Dissipation in an RLC Series