An engineer designed a transformer to convert 120 V (rms) to 6.0 V (rms). The number of turns in the primary is 540, and the secondary current is 610 mA at an output voltage of 6.0 V (rms).
-How many turns are in the secondary?
A)90
B)27
C)5
D)3 240

Question

An engineer designed a transformer to convert 120 V (rms) to 6.0 V (rms). The number of turns in the primary is 540, and the secondary current is 610 mA at an output voltage of 6.0 V (rms). 
-How many turns are in the secondary?
A)90
B)27
C)5
D)3 240

Quizplus · Accepted Answer

The number of turns in the secondary can be found using the transformer equation: $V_p/V_s = N_p/N_s$, where $V_p$ and $V_s$ are the primary and secondary voltages, respectively, and $N_p$ and $N_s$ are the number of turns in the primary and secondary, respectively. Substituting the given values: $120V/6.0V = 540/N_s$, solving for $N_s$ gives $N_s = 27$.

An Engineer Designed a Transformer to Convert 120 V (Rms)