An electromagnetic wave with a peak electric field component of 1.11 × 10² N/C has what associated peak magnetic field value? (ε₀ = 8.85 × 10−¹² C²/N⋅m²,μ₀ = 4π × 10−⁷ T⋅m/A and c = 3.00 × 10⁸ m/s) A)3.33E+10 T B)2.70E+6 T C)3.70E-7 T D)4.65E-13 T E)7.34E+3 T

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Quizplus · Accepted Answer

The peak magnetic field value $B$ of an electromagnetic wave can be found using the relation $B = \frac{E}{c}$, where $E$ is the peak electric field component and $c$ is the speed of light. Given $E = 1.11 \times 10^{12} \, \text{N/C}$ and $c = 3.00 \times 10^8 \, \text{m/s}$, $B = \frac{1.11 \times 10^{12}}{3.00 \times 10^8} = 3.70 \times 10^{-7} \, \text{T}$.

An Electromagnetic Wave with a Peak Electric Field Component of 1.11