A Young's double-slit apparatus is set up.The source wavelength is 424 nm,and the double-slit spacing is 0.0560 mm.At what distance from the double slits should the screen be placed if the spacing between alternating bright fringes is to be 1.60 cm? (1 nm = 10−⁹ m) A)211 m B)2.11 m. C)0.825 m D)279 m E)2.11 m..

Question

Quizplus · Accepted Answer

The fringe spacing (Δy) is given by the formula Δy = (λL)/d, where λ is the wavelength, L is the distance to the screen, and d is the slit spacing. Rearranging for L gives L = (Δy * d)/λ. Substituting the given values: Δy = 1.60 cm = 0.016 m, λ = 424 nm = 424 x 10^-9 m, and d = 0.0560 mm = 0.0560 x 10^-3 m, we find L = (0.016 * 0.0560 x 10^-3)/(424 x 10^-9) = 2.11 m.

A Young's Double-Slit Apparatus Is Set Up