Light of wavelength 420 nm is incident on a slit of width 0.20 mm,and a diffraction pattern is produced on a screen that is 1.80 m from the slit.What is the width of the central bright fringe? (1 nm = 10−⁹ m)

Question

Quizplus · Accepted Answer

The width of the central bright fringe in a single-slit diffraction pattern is given by the formula: $ W = \frac{2 \lambda L}{a} $, where $ \lambda $ is the wavelength, $ L $ is the distance to the screen, and $ a $ is the slit width. Substituting the given values: $ \lambda = 420 \times 10^{-9} $ m, $ L = 1.80 $ m, and $ a = 0.20 \times 10^{-3} $ m, we find $ W = \frac{2 \times 420 \times 10^{-9} \times 1.80}{0.20 \times 10^{-3}} = 7.56 \times 10^{-3} $ m, which is approximately 7.6E-3 m.

Light of Wavelength 420 Nm Is Incident on a Slit