If the mass of a proton is 1.67 × 10−²⁷ kg,what is the rest energy of the proton? (c = 3.00 × 10⁸ m/s and 1 eV = 1.6 × 10−¹⁹ J) A)1.2 × 10⁸ eV B)3.7 × 10⁸ eV C)4.1 × 10⁸ eV D)9.4 × 10⁸ eV

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Quizplus · Accepted Answer

The rest energy of a proton can be calculated using Einstein's equation $E = mc^2$, where $m = 1.67 \times 10^{-27}$ kg is the mass of the proton and $c = 3.00 \times 10^8$ m/s is the speed of light. Substituting these values, $E = (1.67 \times 10^{-27} \text{ kg}) \times (3.00 \times 10^8 \text{ m/s})^2 = 1.503 \times 10^{-10}$ J. To convert this energy to electronvolts (eV), use the conversion factor $1 \text{ eV} = 1.6 \times 10^{-19}$ J, resulting in $E = \frac{1.503 \times 10^{-10} \text{ J}}{1.6 \times 10^{-19} \text{ J/eV}} = 9.4 \times 10^{8} \text{ eV}$.

If the Mass of a Proton Is 1