An electron of mass 9.11 × 10−³¹ kg moves with a speed of 0.660c.What is its kinetic energy? (c = 3.00 × 10⁸ m/s) A)2.71E-14 J B)1.09E-13 J C)8.20E-14 J D)1.79E-14 J E)2.04E-14 J

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Quizplus · Accepted Answer

The kinetic energy (KE) of a relativistic particle can be calculated using the formula: KE = ($\gamma - 1$)mc^2, where $\gamma = \frac{1}{\sqrt{1 - \frac{v^2}{c^2}}}$, m is the mass of the particle, v is its velocity, and c is the speed of light. Given that v = 0.660c and m = 9.11 × 10^-31 kg, we first calculate $\gamma$, then use it to find KE. The calculation yields a kinetic energy of approximately 2.71 × 10^-14 J, making option A correct.

An Electron of Mass 9