If an x-ray machine were designed to operate at two separate accelerating voltages,one double the other,how would the shortest wavelength,λ_min,hν,and the maximum frequency,f_max,hν,at the higher voltage compare to those (λ_min,lv,f_max,lv) at the lower voltage?
Λ_min,hv/ λ_min,lv = ________,f_max,hv/ f_max,lv =________:

Question

Quizplus · Accepted Answer

The shortest wavelength is inversely proportional to the voltage (due to the relationship λ_min = hc/eV, where h is Planck's constant, c is the speed of light, e is the electron charge, and V is the voltage), so doubling the voltage halves the shortest wavelength. The maximum frequency is directly proportional to the voltage (since f_max = eV/h), so doubling the voltage doubles the maximum frequency.

If an X-Ray Machine Were Designed to Operate at Two