A beam of photons of wavelength 0.55 nm undergoes Compton scattering from free electrons.
-What is the energy of the photons that emerge at a 35° angle with respect to the incident beam?
A)2.3 keV
B)10.9 keV
C)36.0 keV
D)3.0 keV

Question

A beam of photons of wavelength 0.55 nm undergoes Compton scattering from free electrons.
-​What is the energy of the photons that emerge at a 35° angle with respect to the incident beam?
A)​2.3 keV
B)​10.9 keV
C)​36.0 keV
D)​3.0 keV

Quizplus · Accepted Answer

The correct answer is A.The energy of the photons that emerge at a 35° angle with respect to the incident beam is 2.3 keV. This can be calculated using the Compton scattering formula:```E' = E / (1 + (h / mc)(λ - λ'))```where:* E is the energy of the incident photon* E' is the energy of the scattered photon* h is Planck's constant* m is the mass of the electron* c is the speed of light* λ is the wavelength of the incident photon* λ' is the wavelength of the scattered photonPlugging in the given values, we get:```E' = 12.4 keV / (1 + (6.626 x 10^-34 J s / (9.109 x 10^-31 kg)(3 x 10^8 m/s))(0.55 nm - 0.55 nm * cos(35°)))``````E' = 2.3 keV```

A Beam of Photons of Wavelength 0